Giancoli Physics (5th ed) Chapter 27

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Revision as of 12:28, 1 March 2009 by Cmurray (talk | contribs) (72. A beam of red laser light (wavelength = 633 nm) hits a black wall and is fully absorbed. If this exerts a total force of F = 5.5 nN, how many photons per second are hitting the wall?)
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Contents

Problems

1. Question

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2. Question

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3. Question

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4. Question

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5. Question

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6. Question

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7. Question

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8. Question

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9. Question

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10. Question

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11. Question

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12. What is the energy range in eV, of photons in the visible spectrum, of wavelength 400 nm to 700 nm?

put these in J first
1.77 eV < E < 3.10 eV

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13. Question

4.23 x 10-7 eV

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14. Question

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15. Question

2.4 x 1013 Hz
1.2 x 10-5 m

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16. Question

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17. Question

400 nm

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18. Barium has a work function of 2.48 eV. What is the maximum kinetic energy of electrons if the metal is illuminated by light of wavelength 390 nm? What is their speed?

.70 eV - but also convert this to joules
5.0 x 105 m/s

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19. Question

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20. Question

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21. Question

0.62 eV

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22. Question

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23. Question

1.08 eV
no ejected electtrons

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24. Question

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25. Question

3.75 eV

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26. Question

1.52 MeV

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27. Question

1.9 x 10-24 kg*m/s
6.3 x 10-33 kg2

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28. Question

6.62 x 10-16 m

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29. Question

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30. Question

1.71 MeV
7.24 x 10-13 m

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31. Question

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32. Question

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33. Question

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34. Question

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35. Question

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36. Question

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37. Question

7.2 x 10-12 m

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38. Question

29 V

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39. Question

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40. Question

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41. Question

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42. Question

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43. Question

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44. Question

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45. Question

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46. Question

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47. Question

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48. Question

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49. Question

3.4 eV

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50. Question

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51. Question

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52. Question

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53. Question

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54. Question

(a) 486 nm
(b) 102 nm
(c) 434 nm

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55. Question

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56. Question

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57. Question

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58. Question

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59. Question

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60. Question

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61. Question

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62. Question

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63. Question

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64. Question

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65. Question

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66. Question

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67. Question

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68. Question

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69. Question

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70. Question

4.66 x 1026 photons/s

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71. Question

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72. A beam of red laser light (wavelength = 633 nm) hits a black wall and is fully absorbed. If this exerts a total force of F = 5.5 nN, how many photons per second are hitting the wall?

Use de Broglie's relation of momentum p = h/lambda. Force is just change in momentum/time - so the number of photons per second times the momentum of each would give the force.. (1 nN = 10-9 N)

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73. Question

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74. Question

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75. Question

4.7 x 10-14

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76. Question

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77. Question

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78. Question

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79. Question

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80. Question

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81. Question

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