Difference between revisions of "Net Force"
(→4. What is the acceleration of a 6.0 Kg object hanging on a string that is under a tension of 80. N? 30. N? (Make up positive)) |
(→4. What is the acceleration of a 6.0 Kg object hanging on a string that is under a tension of 80. N? 30. N? (Make up positive)) |
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| Line 41: | Line 41: | ||
F = ma<br><br> | F = ma<br><br> | ||
6 kg * 9.81 m/s = 58.9 N<br><br> | 6 kg * 9.81 m/s = 58.9 N<br><br> | ||
| − | (80 N - 58.9 N) = (6 kg)a<br><br> | + | A. (80 N - 58.9 N) = (6 kg)a<br><br> |
21.1 N = (6 kg)a<br><br> | 21.1 N = (6 kg)a<br><br> | ||
a = 3.5 m/s<sup>2</sup><br><br> | a = 3.5 m/s<sup>2</sup><br><br> | ||
| − | (30 N - 58.9 N) = (6 kg)a<br><br> | + | B. (30 N - 58.9 N) = (6 kg)a<br><br> |
(-28.9 N) = (6 kg)a<br><br> | (-28.9 N) = (6 kg)a<br><br> | ||
a = -4.81 m/s<sup>2</sup> | a = -4.81 m/s<sup>2</sup> | ||
Revision as of 17:55, 11 January 2009
Main Page > Giancoli Physics (5th ed) Solutions > Blank Problem Template
Contents
- 1 About this page
- 2 Problems
- 2.1 1. What is the weight of a 3.4 kg mass?
- 2.2 2. What mass has a weight of 720. N?
- 2.3 3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N) What is the acceleration of the car if he exerts a force of 350. N?
- 2.4 4. What is the acceleration of a 6.0 Kg object hanging on a string that is under a tension of 80. N? 30. N? (Make up positive)
- 2.5 5. Question
- 2.6 6. Question
- 2.7 7. Question
- 2.8 8. Question
- 2.9 9. Question
- 2.10 10. Question
- 2.11 11. Question
- 2.12 12. Question
- 2.13 13. Question
- 2.14 14. Question
- 2.15 15. Question
About this page
All images uploaded for this page must start with the string "Gp5_chapter#_" so the image 16-38.jpg associated with chapter 16 should be uploaded as Gp5_16_16-38.jpg. This way we can avoid conflicts in the image directory, and we can find images easily.
Table of Contents
Problems
1. What is the weight of a 3.4 kg mass?
F = ma
Weight = force
F = 3.4 x 9.8 = 33.32 N
2. What mass has a weight of 720. N?
F = ma
F/a = m
720 N/9.81 m/s = 73.4 m/s
3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N) What is the acceleration of the car if he exerts a force of 350. N?
F = ma
F/m = a
(350 N - 240 N)/980 kg = .112 m/s2
4. What is the acceleration of a 6.0 Kg object hanging on a string that is under a tension of 80. N? 30. N? (Make up positive)
F = ma
6 kg * 9.81 m/s = 58.9 N
A. (80 N - 58.9 N) = (6 kg)a
21.1 N = (6 kg)a
a = 3.5 m/s2
B. (30 N - 58.9 N) = (6 kg)a
(-28.9 N) = (6 kg)a
a = -4.81 m/s2
5. Question
Solution goes here
6. Question
Solution goes here
7. Question
Solution goes here
8. Question
Solution goes here
9. Question
Solution goes here
10. Question
Solution goes here
11. Question
Solution goes here
12. Question
Solution goes here
13. Question
Solution goes here
14. Question
Solution goes here
15. Question
Solution goes here
