Difference between revisions of "Projectile Review Worksheet"

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(1. Marlene jumps off the edge of a cliff and hits the water 1.5 seconds later, about 4.5 m from the base of the cliff. What height was the cliff? With what speed did she leave the edge?)
(1. Marlene jumps off the edge of a cliff and hits the water 1.5 seconds later, about 4.5 m from the base of the cliff. What height was the cliff? With what speed did she leave the edge?)
Line 19: Line 19:
 
u = <br>
 
u = <br>
 
v = <br>
 
v = <br>
a = <br>
+
a = 0<br>
 
t = 1.5 s<br>
 
t = 1.5 s<br>
  
 
|
 
|
 
s = <br>
 
s = <br>
u = 0 (purely horizontal velocity)<br>
+
u = 0 (cliff)<br>
 
v = <br>
 
v = <br>
a = <br>
+
a = -9.81 m/s/s<br>
 
t = 1.5 s<br>
 
t = 1.5 s<br>
  

Revision as of 10:01, 4 November 2008

Main Page > Solutions to Worksheets > Projectile Review Worksheet

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All images uploaded for this page must start with the string "Projectile_Review_Worksheet_" so the image 16-38.jpg associated with this page should be uploaded as Projectile_Review_Worksheet_16-38.jpg. This way we can avoid conflicts in the image directory, and we can find images easily.
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Problems

1. Marlene jumps off the edge of a cliff and hits the water 1.5 seconds later, about 4.5 m from the base of the cliff. What height was the cliff? With what speed did she leave the edge?

So we fill in our H/V suvat:

H V

s = 4.5 m
u =
v =
a = 0
t = 1.5 s

s =
u = 0 (cliff)
v =
a = -9.81 m/s/s
t = 1.5 s

Then we can calculate

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2. Question

Solution goes here

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3. Question

Solution goes here

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4. Question

Solution goes here

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5. Question

Solution goes here

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6. Question

Solution goes here

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