Difference between revisions of "6.1 - Work and Energy"
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− | [[Main Page]] > [[ | + | [[Main Page]] > [[Solutions to Worksheets]] > 6.1-Work and Energy<br /> |
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==About this page== | ==About this page== | ||
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==Problems== | ==Problems== | ||
− | ===1. | + | ===1. A 5.2 kg object speeds up from 3.1 m/s to 4.2 m/s. What is the change in kinetic energy? (21 J)=== |
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Solution goes here | Solution goes here | ||
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[[#top | Table of Contents]] | [[#top | Table of Contents]] | ||
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− | ===2. | + | ===2. A 1.2 HP motor (1 HP = 745.7 Watts) is used to raise a 1300 kg Land Rover 5.7 m up into a tree. What time will it take? (81 s)=== |
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Solution goes here | Solution goes here | ||
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[[#top | Table of Contents]] | [[#top | Table of Contents]] | ||
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− | ===3. | + | ===3. A massless spring with a spring constant of 34 N/m is compressed 5.8 cm horizontally and used to shoot an 18 gram marble across a frictionless table. What is the speed of the marble? (2.5 m/s)=== |
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Solution goes here | Solution goes here | ||
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[[#top | Table of Contents]] | [[#top | Table of Contents]] | ||
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− | ===4. | + | ===4. A 3.4 kg bowling ball hanging from the ceiling on a long string swings from side to side like a pendulum. When it is 15 cm above its lowest point on the left side, I shove it with a force of 11 N for a distance of .35 m in the direction it is going. How high will it swing on the other side? (Neglect friction) (27 cm)=== |
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Solution goes here | Solution goes here | ||
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[[#top | Table of Contents]] | [[#top | Table of Contents]] | ||
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− | ===5. | + | ===5. A 580 kg rollercoaster is going 7.5 m/s on the top of a 1.2 m tall hill, how fast is it going on top of a 3.5 m tall hill? (Neglect friction) (3.3 m/s)=== |
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Solution goes here | Solution goes here |
Latest revision as of 11:34, 3 March 2009
Main Page > Solutions to Worksheets > 6.1-Work and Energy
Contents
- 1 About this page
- 2 Problems
- 2.1 1. A 5.2 kg object speeds up from 3.1 m/s to 4.2 m/s. What is the change in kinetic energy? (21 J)
- 2.2 2. A 1.2 HP motor (1 HP = 745.7 Watts) is used to raise a 1300 kg Land Rover 5.7 m up into a tree. What time will it take? (81 s)
- 2.3 3. A massless spring with a spring constant of 34 N/m is compressed 5.8 cm horizontally and used to shoot an 18 gram marble across a frictionless table. What is the speed of the marble? (2.5 m/s)
- 2.4 4. A 3.4 kg bowling ball hanging from the ceiling on a long string swings from side to side like a pendulum. When it is 15 cm above its lowest point on the left side, I shove it with a force of 11 N for a distance of .35 m in the direction it is going. How high will it swing on the other side? (Neglect friction) (27 cm)
- 2.5 5. A 580 kg rollercoaster is going 7.5 m/s on the top of a 1.2 m tall hill, how fast is it going on top of a 3.5 m tall hill? (Neglect friction) (3.3 m/s)
About this page
All images uploaded for this page must start with the string "Gp5_chapter#_" so the image 16-38.jpg associated with chapter 16 should be uploaded as Gp5_16_16-38.jpg. This way we can avoid conflicts in the image directory, and we can find images easily.
Table of Contents
Problems
1. A 5.2 kg object speeds up from 3.1 m/s to 4.2 m/s. What is the change in kinetic energy? (21 J)
Solution goes here
2. A 1.2 HP motor (1 HP = 745.7 Watts) is used to raise a 1300 kg Land Rover 5.7 m up into a tree. What time will it take? (81 s)
Solution goes here
3. A massless spring with a spring constant of 34 N/m is compressed 5.8 cm horizontally and used to shoot an 18 gram marble across a frictionless table. What is the speed of the marble? (2.5 m/s)
Solution goes here
4. A 3.4 kg bowling ball hanging from the ceiling on a long string swings from side to side like a pendulum. When it is 15 cm above its lowest point on the left side, I shove it with a force of 11 N for a distance of .35 m in the direction it is going. How high will it swing on the other side? (Neglect friction) (27 cm)
Solution goes here
5. A 580 kg rollercoaster is going 7.5 m/s on the top of a 1.2 m tall hill, how fast is it going on top of a 3.5 m tall hill? (Neglect friction) (3.3 m/s)
Solution goes here