Difference between revisions of "Skill Set 03.1"
From TuHSPhysicsWiki
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(→1. Find the components of the vector.) |
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===1. Find the components of the vector.=== | ===1. Find the components of the vector.=== | ||
<blockquote> | <blockquote> | ||
| − | Since the angle given is the same as the trig angle, we can use 17 in our equations. | + | Since the angle given is the same as the trig angle, we can use 17 in our equations.<br><br> |
| − | 32cos(17) = '''30.60 m x''' | + | 32cos(17) = '''30.60 m x'''<br> |
32sin(17) = '''9.356 m y''' | 32sin(17) = '''9.356 m y''' | ||
</blockquote> | </blockquote> | ||
Revision as of 10:04, 12 February 2009
Main Page > IB Physics Skill Sets > Skill Set 03.1
Contents
1. Find the components of the vector.
Since the angle given is the same as the trig angle, we can use 17 in our equations.
32cos(17) = 30.60 m x
32sin(17) = 9.356 m y
2. Question
Solution goes here
3. Question
Solution goes here
4. Question
Solution goes here
5. Question
Solution goes here
