View source for Projectile Review Worksheet

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==Problems==
===1. Marlene jumps off the edge of a cliff and hits the water 1.5 seconds later, about 4.5 m from the base of the cliff.  What height was the cliff?  With what speed did she leave the edge?===
<blockquote>
So we fill in our H/V suvat:<br>
{| border="1" cellpadding="10"
|+
!width="150"|H
!width="150"|V
|-
|
s = 4.5 m<br>
u = <br>
v = <br>
a = 0<br>
t = 1.5 s<br>

|
s = <br>
u = 0 (cliff)<br>
v = <br>
a = -9.81 m/s/s<br>
t = 1.5 s<br>

|-
|}

We are looking for vertical displacement (s) and horizontal velocity (u). We can solve for each variable separately. For vertical displacement, we can use the formula<br><br>

s = ut + 1/2at<sup>2</sup><br><br>

s = (0 m/s)(1.5 s) + (.5)(-9.81 m/s<sup>2</sup>)(1.5 s)<sup>2</sup><br><br>

s = 11.03625 m = 11 m<br><br>

For horizontal velocity, we can use the formula<br><br>

u = s/t<br><br>

u = (4.5 m) / (1.5 s)<br><br>

u = 3 m/s


</blockquote>
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===2. Question===
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Solution goes here
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===3. Question===
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===4. Question===
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Solution goes here
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===5. Question===
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Solution goes here
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===6. Question===
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Solution goes here
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