Difference between revisions of "Skill Set 03.1"
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Converting the 23<sup>o</sup> angle to a trig angle is done by subtracting it by 360, since the angle is just below the 0 or 360<sup>o</sup> line. Using our new angle, 337<sup>o</sup>, we can solve for the components.<br><br> | Converting the 23<sup>o</sup> angle to a trig angle is done by subtracting it by 360, since the angle is just below the 0 or 360<sup>o</sup> line. Using our new angle, 337<sup>o</sup>, we can solve for the components.<br><br> | ||
| − | 15cos(337) = '''13.81 m x''' | + | 15cos(337) = '''13.81 m x'''<br> |
15sin(337) = '''-5.861 m y''' | 15sin(337) = '''-5.861 m y''' | ||
</blockquote> | </blockquote> | ||
Revision as of 11:07, 12 February 2009
Main Page > IB Physics Skill Sets > Skill Set 03.1
Contents
1. Find the components of the vector.
Since the angle given is the same as the trig angle, we can use 17o in our equations.
32cos(17) = 30.60 m x
32sin(17) = 9.356 m y
2. Find the components of the vector.
Converting the 23o angle to a trig angle is done by subtracting it by 360, since the angle is just below the 0 or 360o line. Using our new angle, 337o, we can solve for the components.
15cos(337) = 13.81 m x
15sin(337) = -5.861 m y
3. Question
Solution goes here
4. Question
Solution goes here
5. Question
Solution goes here
