Difference between revisions of "Projectile Review Worksheet"

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Problems

1. Marlene jumps off the edge of a cliff and hits the water 1.5 seconds later, about 4.5 m from the base of the cliff. What height was the cliff? With what speed did she leave the edge?

So we fill in our H/V suvat:

H	V
s = 4.5 m u = v = a = 0 t = 1.5 s	s = u = 0 (cliff) v = a = -9.81 m/s/s t = 1.5 s

We are looking for vertical displacement (s) and horizontal velocity (u). We can solve for each variable separately. For vertical displacement, we can use the formula

s = ut + 1/2at²

s = (0 m/s)(1.5 s) + (.5)(-9.81 m/s²)(1.5 s)²

s = 11.03625 m = 11 m

For horizontal velocity, we can use the formula

u = s/t

u = (4.5 m) / (1.5 s)

u = 3 m/s

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2. Question

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3. Question

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