Difference between revisions of "Net Force"

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(3. Question)
(3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N) What is the acceleration of the car if he exerts a force of 350. N?)
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===3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N)  What is the acceleration of the car if he exerts a force of 350. N?===
 
===3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N)  What is the acceleration of the car if he exerts a force of 350. N?===
 
<blockquote>
 
<blockquote>
Solution goes here
+
F = ma<br><br>
 +
F/m = a<br><br>
 +
(350 N -240 N)/980 kg = .112 m/s<2>Superscript text</2>
 
</blockquote>
 
</blockquote>
 
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Revision as of 17:39, 11 January 2009

Main Page > Giancoli Physics (5th ed) Solutions > Blank Problem Template

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Problems

1. What is the weight of a 3.4 kg mass?

F = ma

Weight = force

F = 3.4 x 9.8 = 33.32 N

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2. What mass has a weight of 720. N?

F = ma

F/a = m

720 N/9.81 m/s = 73.4 m/s

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3. Bob must exert 240. N of force on a 980. Kg car to move it at a constant speed up an incline. (The frictional and gravity force is 240. N) What is the acceleration of the car if he exerts a force of 350. N?

F = ma

F/m = a

(350 N -240 N)/980 kg = .112 m/s<2>Superscript text</2>

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4. Question

Solution goes here

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5. Question

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6. Question

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7. Question

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8. Question

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9. Question

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10. Question

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11. Question

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12. Question

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13. Question

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14. Question

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15. Question

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